What is the nozzle reaction for a smooth-bore 1.5-inch tip operating at a nozzle pressure of 50 psi?

Answer: C — 168.75 pounds

To determine the nozzle reaction of a smooth-bore nozzle, you can use the formula: \[ \text{Nozzle Reaction (NR)} = \frac{(0.1) \times (N^2)}{2} \] where \( N \) is the nozzle pressure in psi. In this case, for a smooth-bore nozzle, the formula can be more broadly represented as: \[ \text{NR} = 1.57 \times d^2 \times P \] where - \( d \) is the diameter of the nozzle in inches (for a 1.5-inch nozzle, \( d = 1.5 \)), - \( P \) is the nozzle pressure in pounds per square inch (psi). Plugging in the values: 1. Convert the diameter into a decimal: \( 1.5 \) inches. 2. Use the nozzle pressure provided: \( 50 \) psi. 3. The calculation becomes: \[ \text{NR} = 1.57 \times (1.5^2) \times 50 \] \[ \text{NR} = 1.57 \times 2.25 \times 50 \] \[ \