A 2-axle truck has a wheelbase of 5.0 meters. A single concentrated machinery load weighing 6,000 kg is loaded on the cargo bed. The center of gravity of the load is located exactly 1.5 meters ahead of the rear axle (3.5 meters behind the front axle). Using the lever law ($F_{rear} = F_{load} · (3.5)/(5.0)$), what portion of the payload weight is transferred to the rear axle?

1. 4,200 kg (70% of payload weight)
2. 1,800 kg (30% of payload weight)
3. 3,000 kg (50% of payload weight)
4. 5,000 kg (83% of payload weight)